Find the m of PbSO4 produced when 39.5 g Pb reacts with an excess of lead(iv) oxide and sulfuric acid.?

39.5 g Pb / 207.2 g Pb/mol = 0.191 mol of Pb x (2 mols of PbSO4/1 mol of Pb) = 0.382 mols of PbSO4 x (303.2 g PbSO4/1 mol PbSO4) = 115.8224 g